bucherc
Entries "My entries":

Friday, June 1, 2007

Scribe post

Learning target: converting fractions to percentages,and converting percents to fractions.

Example: To convert a fraction to a percent you have to create a proportion. If you don't no how to make a porportion check out Robinsong's scribe post. Let's say you have to convert 1/8 into a percent. You would create a porportion which would look like this; 1/8=x/100. Then, you cross multiply: 1*100=100 and x*8=8x. Remember to always put the number before the variable. next, you divide 8x by 8. The solution is x. The key to that is to get the variable all by itself. Following that, you have to divide 100 by 8 because aftter all balance is the key to solving any problem (according to Mr.Tubbs). The solution to this problem is 12.5. so 1/8 equals 12.5 percent. Now let's try converting percemts to fractions. let's say you are trying to make 5 percent a fraction. First, you would make 5 percent into a fraction. This would be 1/20 (I simplified 5/100). Remeber to always put your percentage number over 100 first then simplify.

Check out this link:

http://www.sosmath.com/algebra/fraction/frac7/frac7.html

I found a cool shortcut:

http://video.google.com/videoplay?docid=6213689731166287913&q=converting+fractions+to+percents&hl=en 

 

 

»7:28 PM    »Write comment    

Posted by: bucherc
Tuesday, March 27, 2007

Scribe post

Learning Target: Developing the area for rectangles, triangles, and parrallelograms.

Formulas: To find the  area of a triangle you apply the equation 1/2 (base * height).

                                                               To find the area of a rectangle you apply the

                                                               equation length * width.

 

 To find the area for a parrallelogram you apply the equation base * height.

Now let's do some example problems:

If a triangle has the base of  3 inches and the height of 5 inches what is the area?

If you got 7.5 square inches you are correct! You would first multiply the base by the height.

The equation would be 3 times 5 = 15 square inches. 

Then divide the product by 2.  The equation would be 15/2 = 7.5 square inches.

 

If a rectangle has a width of 15 inches and the length is 4 inches what is the area?

If you got 60 square inches you are correct! 15 inches * 4 inches= 60 square inches.

 

If you have a parallelogram that has a base of 11 inches and a height of 8 inches what is the area?

If you got 89 square inches you are wrong 

The correct answer is 88 square inches. The equation for this is 11 inches * 8 inches= 88 square inches.

 

Check out this video about the area of a rectangle:

http://www.youtube.com/watch?v=ONUhZmBIjPI

 

 

 

»12:28 AM    »1 comments    

Posted by: bucherc
Saturday, November 11, 2006

Scribe Post #3

Learning Target

 Todays learning target was using the prime factorization of composite numbers to find the greatest common factor (GCF), and the least common multiple (LCM).

Example Problem

                              16                                  8

                              /\                                 /\                          

                          8   X  2                        4    x    2

                         /\                                /\

                      4  X  2                          2 X 2

                     /\

                   2 X 2

 2X2X2X2=16                                        2X2X2 = 8

  The GCF (Greatest Common Factor) is eight. This is because each of the numbers has two three times in it ( 2x2x2=8).

  The LCM (Least Common Multiple) is sixteen. You find this by making a list of the multiples for each number:

8:8,16,24,32 and

16:16,32,48 then selecting the lowest number in both lists = 16.

Or you could do a multiplication problem . For this problem it would be 2x2x2x2=16. You do this because it contains all the factors required for making both eight and sixteen.

Lesson

You find the GCf by using prime factorization. First you find all the prime factors for each number.  Then you determine the product of all the prime factors that occur for both numbers.  This product is the GCF.

To find the LCM, you make a list of the first of the first four or five multiples for each number and look for the lowest number that is in both lists.  If you don't find one, do the next five multiples and repeat until you find the same number in each list.  This is the LCM. Or you can use prime factorization. Once you find the prime factors for both numbers the LCM is the product of all the prime factors of both numbers without any repeted factors.

Check out this link:

http://mathworld.wolfram.com/LeastCommonMultiple.html

  

                           

              

»4:12 AM    »2 comments    

Posted by: bucherc
Modified on November 11, 2006 at 4:13 AM
Wednesday, October 25, 2006

SCRIBE POST 1

LEARNING TARGET

Estimate sums and diferences using decimals and fractions. 

EXAMPLE PROBLEM 

12.34 + 45.78=

12 + 46=58

LESSON 

TO ESTIMATE A SUM, YOU ROUND EACH NUMBER TO THE NEAREST WHOLE NUMBER THEN ADD ALL OF THE NUMBERS UP TO GET THE SUM.

TO ESTIMATE A DIFFERENCE, YOU ROUND ALL OF THE NUMBERS TO THE NEAREST WHOLE AND SUBTRACT THEM TO GET THE DIFFERENCE.

 EXAMPLE OF DECIMAL

THIS IS PI

 

 

 

»12:55 AM    »Write comment    

Posted by: bucherc
Tuesday, October 24, 2006

Scribe Post

default

Learning Target:

The learning target for this lesson is, using strategies to develop formulas for finding the circumference of circles.

Example Problem:

If you measure the diameter and the circumference of a circle you can calculate pi. Pi is equal to the circumference divided by the diameter. This is true for all circle figures.

If the diameter of the shape is 15 centimeters and you want to find the circumference, you would do the equation 15 times pi(which is equal to 3.14 roughly). So the solution to the equation would be 47.1 centimeters, that is the circumference.

Lesson:

The circumference of a circle is the distance  around it. The diameter is the distance across the circle at its widest point. The ratio of the circumference and the diameter is always the same for every circle. This ratio is called pi (which is equal to 3.14). If you know the diameter of a circle, you can multiply it by pi to find the circumference. On the other hand, if you know the circumference you can divide it by pi to get the diameter.

Check out these cool activities:

  http://www.aaamath.com/geo612-circumference-circle.html#pgtp

  

http://www.bbc.co.uk/scotland/education/bitesize/standard/mathsI/area/circim_circle_rev2.shtml

http://www.mathgoodies.com/lessons/vol2/circumference.html

»12:01 AM    »Write comment    

Posted by: bucherc
Modified on October 24, 2006 at 12:06 AM